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Sam Bede
Joined: 05 Aug 2007 Posts: 2
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Posted: Sat Apr 21, 2007 1:30 pm Post subject: Can anyone solve this little problem? |
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Hi
Sorry to be a dunce, but I'm sure some maths whiz can solve this.
I'd really appreciate your help.
I have a value, call it X. And I know it's risen over the year by a
percentage, say Y.
How do I calculate what the original value of X is?
My attempts have been missing the mark. Your help would be greatly
appreciated.
Thanks so much.
Sam
Archived from group: uk>education>maths |
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Dan Wood
Joined: 05 Aug 2007 Posts: 4
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Posted: Sat Apr 21, 2007 2:45 pm Post subject: Re: Can anyone solve this little problem? |
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Sam Bede wrote:
> Hi
>
> Sorry to be a dunce, but I'm sure some maths whiz can solve this.
>
> I'd really appreciate your help.
>
> I have a value, call it X. And I know it's risen over the year by a
> percentage, say Y.
>
> How do I calculate what the original value of X is?
>
> My attempts have been missing the mark. Your help would be greatly
> appreciated.
>
> Thanks so much.
> Sam
>
>
>
Lots of ways to do this. Perhaps the easiest for you to think about
would be to imagine your original X is '100 percent'.
So when it rises by Y, you end up with '100 and Y percent'
So, to go backwards, DIVIDE your new amount by '100 and Y' to find one
percent, and then multiply by 100...
Hope that makes sense!
Dan. |
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~Bitzchick~
Joined: 05 Aug 2007 Posts: 18
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Posted: Sat Apr 21, 2007 2:31 pm Post subject: Re: Can anyone solve this little problem? |
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Sam Bede wrote:
> Hi
>
> Sorry to be a dunce, but I'm sure some maths whiz can solve this.
>
> I'd really appreciate your help.
>
> I have a value, call it X. And I know it's risen over the year by a
> percentage, say Y.
>
> How do I calculate what the original value of X is?
>
> My attempts have been missing the mark. Your help would be greatly
> appreciated.
>
> Thanks so much.
> Sam
X = original amount
X/100 = percentage of X
Y is new value of X after it has risen by X/100
So
New amount X has risen by X+ X/100 = Y
Factorising:
X(1+0.01) = Y
X (1.01) =Y
Therefore X = Y/1.01
sheri |
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Stan Brown
Joined: 05 Aug 2007 Posts: 233
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Posted: Sat Apr 21, 2007 11:45 am Post subject: Re: Can anyone solve this little problem? |
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Sat, 21 Apr 2007 09:30:46 GMT from Sam Bede
spam.com>:
> I have a value, call it X. And I know it's risen over the year by a
> percentage, say Y.
>
> How do I calculate what the original value of X is?
If something rises by 15%, its new value is 1 + 15% of its old value.
15% = 15/100, so the new value is (1 + 15/100) times the old value,
or (1 + 0.15) times the old value, or 1.15 times the old value.
Your value rose by Y%, so the new value is (1 + Y/100) times the old
value Let's call the old value V. Then you have
(1 + Y/100) * V = X
You know X and Y and you want to know V.
Divide:
V = X / (1 + 100/Y)
Now plug and chug. Example: X = 1100 pounds, Y = 20%. Then
1 + 100/Y = 1.20
V = 1100 pounds / 1.20 = about 916.67 pounds
Check: 20% of 916.67 is 183.33. Adding the amount of increase to the
original gives 916.67+183.33 = 1100.00.
--
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
http://OakRoadSystems.com/ |
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Sam Bede
Joined: 05 Aug 2007 Posts: 2
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Posted: Sun Apr 22, 2007 1:26 pm Post subject: Re: Can anyone solve this little problem? |
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THANKS for helping with this.
I couldn't work it out and appreciate your kind assistance.
Sam..
"Sam Bede" wrote in message $M.8954@news-server.bigpond.net.au...
> Hi
>
> Sorry to be a dunce, but I'm sure some maths whiz can solve this.
>
> I'd really appreciate your help.
>
> I have a value, call it X. And I know it's risen over the year by a
> percentage, say Y.
>
> How do I calculate what the original value of X is?
>
> My attempts have been missing the mark. Your help would be greatly
> appreciated.
>
> Thanks so much.
> Sam
>
>
> |
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CWatters
Joined: 05 Aug 2007 Posts: 6
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Posted: Sun Jul 15, 2007 1:58 pm Post subject: Re: Can anyone solve this little problem? |
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"Sam Bede" wrote in message$M.11258@news-server.bigpond.net.au...
> THANKS for helping with this.
>
> I couldn't work it out and appreciate your kind assistance.
>
> Sam..
As my teachers would say...
as an exercise now try working out the original sum if you have £X at the
end of TWO years growth at Y% per year compounded.
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